lim menuju 0 sin2x per 3-√2x+9 =

Bab Limit
Matematika SMA Kelas X

lim ((sin 2x) / (3 - √(2x + 9)))
x→0
= lim ((sin 2x) (3 + √(2x + 9)) / (3² - √(2x + 9)²)))
  x→0
= lim ((sin 2x) (3 + √(2x + 9)) / (9 - 2x - 9))
  x→0
= lim ((sin 2x) . (3 + √(2x + 9)) / (-2x)
  x→0
= - (3 + √(0 + 9))
= - (3 + 3)
= -6