Persamaan kuadrat x^2-3x-4=0 mempunyai akar x1 dan x2 .(x1/x2-1) dan (x2/x1-1) adalah

x^2-3x-4=0
(x+1)(x-4)
x1=-1 x2=4

(x1/x2-1) = (-1/4-1) = -1/3
(x2/x1-1) = (4/-1-1) = -2

x^2 - 3x - 4 = 0
(x-4) (x+1) = 0
x1= 4 / x2= -1

(x1/x2-1) = -4-1 = -5
(x2/x1-1) = -1/4 - 1 = -5/4