^ylogx = 3 ^ylogz = 2 Nilai dari ^(y/x)log (z/y)

^ylog z = 1 / ^zlog y
maka ^zlog y = 1/2
^zlog y . ^ylog x = 1/2 . 3
^zlog x = 3/2
= {^(y/x) log z} - {^(y/x) log y}
= {1 / ^z log (y/x)} - {1 / ^y log (y/x)}
= {1 / (^zlog y - ^zlog x)} - {1 / (^ylog y - ^ylog x)}
= {1 / (½ - 3/2)} - {1 / (1 - 3)}
= {1 / (-½)} - {1 / -2}
= -2 + 1/2
= -1½