bismillah, saya telah menjawab a dan b, adakah yg bisa mengerjakan c dan d?

c.)
[tex]x = -1 \\ \frac{1}{x+p} - \frac{3}{x-p} = 2 \\ \frac{1}{-1+p} - \frac{3}{-1-p} = 2 \\ \frac{1(-1-p)-3(-1+p)}{(-1+p)(-1-p)} = 2 \\ \frac{-1-p+3-3p}{1-p^{2}} = 2 \\ 2 - 4p = 2(1-p^{2}) \\ 2 - 4p = 2-2p^{2} \\ -4p=-2p^{2} \\ 2p^{2}-4p=0 \\ p^{2}-2p=0 \\ p(p-2) = 0 \\ p = 0 | p-2 = 0 \\ p = 0 | p=2[/tex]

d.)
[tex]x = 4 \\ 4x^{2}-4x=p^{2}-2p \\ \\ 4(4)^{2}-4(4) = p^{2}-2p \\ 64-16 = p^{2}-2p \\ 48 = p^{2}-2p \\ p^{2}-2p-48 = 0 \\ (p+6)(p-8) = 0 \\ p+6=0 | p-8 = 0 \\ p=-6 | p = 8[/tex]

Jika ada kekeliruan atau tidak paham, mohon segera tulis di komentar.