jika y = (2x -3)² maka dy/dx =.... Tolong bantuan y + pke cara ny

[tex]y = (f(x))^{n}\\ \frac{dy}{dx} = n \times (f(x))^{n-1} \times \frac{df(x)}{dx} \\ \\ y = (2x-3)^{2} \\ \frac{dy}{dx} = 2 \times (2x-3)^{2-1}\times (2) \\ \frac{dy}{dx} = (4) \times(2x-3) \\ \frac{dy}{dx} = 8x-12[/tex]

Gunakan rumus teorema rantai

Rumus:
dy/dx = dy/du . du/dv . dv/dx

Pembahasan:
Misalkan:
u = (2x - 3)
y = u²

Maka ↓↓↓
dy/du = 2u ; du/dx = 2

dy/dx = dy/du . du/dx
dy/dx = 2u . 2
dy/dx = 2(2x - 3) . 2
dy/dx = 4(2x - 3)
dy/dx = 8x - 12