hitunglah volume dari gas gas berikut: a. 1,5 mol gas amonia(STP) B.320 g gas oksigen(RTP) C. 6,02X10^24 molekul gas nitrogen(p=2atm,T=27derajatC,R=0,082 I.atm/

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Nomor A
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Diketahui :
Jumlah mol, n = 1,5 mol
keadaan STP (Standard Temperature Pressure)
T = 0°C = 273 K
P = 1 atm = 10⁵ Pa
konstanta gas umum, R = 8,31 J/mol.K

tanya :
Volume, V = ___?

Jawab :
P.V = n.R.T

V = (n.R.T) / P

V = (1,5. 8,31. 273) / 10⁵

V = 3402,945 x 10⁻⁵ m³

V = 0,034 m³
V = 34 dm³
V = 34 liter



Nomor B
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diketahui :
massa gas, m = 320 gram
Mr oksigen, Mr = 32

keadaan STP (Standard Temperature Pressure)
T = 0°C = 273 K
P = 1 atm = 10⁵ Pa
konstanta gas umum, R = 8,31 J/mol.K

tanya :
Volume, V = ___?

Jawab :
P.V = n.R.T

P.V = (m/Mr). R.T

V = (m/Mr). R.T / P

V = (320 / 32). 8,31.273 / 10⁵

V = 22686,3 / 10⁵

V = 0,2269 m³

V =  226,9 dm³

V = 226,9 Liter


Nomor C
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Diketahui :
Jumlah molekul, N = 6,02 x 10²⁴ molekul
P = 2 atm = 2 x 10⁵ Pa
T = 27°C = 300 K
R = 0,082 L.atm / mol.K
konstanta Boltzmann, k = 1,38 x 10⁻²³ J/K

Tanya :
Volume, V = ___?

Jawab :

P.V = N.k.T

V = N.k.T / P

V = 6,02 x 10²⁴. 1,38 x 10⁻²³. 300 / 2 x 10⁵

V = 12,4614 x 10⁻² m³

V = 0,124614 m³

V = 124,614 dm³

V = 124,614 liter


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