Diketahui f (x) =3x-5 dan g(x) =x²-6x,maka rumus (f0g) (x) adalah

f (x) =3x-5
g(x) =x²-6x
(f0g) (x)=??

(FoG)(x)= 3(x²-6x)-5
=3x²-18x-5

(fog) (x) = f(g(x)) =f(x²-6x)=3(x²-6x)-5=3x²-18x-5

jadi, rumus (fog) (x) = 3x²-18x-5