• AC/sin ABC = BC/sin BAC
    16/sin 30° = 16√2/sin BAC
    16/(1/2) = 16√2/sin BAC
    16 x sin BAC = 16√2 x 1/2
    16 sin BAC = 8√2
    sin BAC = 8√2/16
    sin BAC = 1/2 √2
    BAC = arc sin 1/2√2 = 45°

    Jadi tan sudut BAC =
    tan 45° = 1

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