turunan fungsi pertama dari f(x)=2/3x^3-4/2x^2-4x+1

u = 2/3x^3 - 4 , v = 2x^2 - 4x + 1
u' = 2x^2 , v' = 4x - 4
f'x = (u'.v - u.v')/v^2
=(2x^2(2x^2 - 4x + 1) - (2/3x^3 - 4)(4x - 4)) /
(2x^2 - 4x + 1)^2
=( 4x^4 - 8x^3 + 2x^2) - (8/3x^4 - 8/3x^3
- 16x - 16) / (2x^2 - 4x + 1)^2
= (4x^4 - 8/3x^4 - 8x^3 + 8/3x^3 + 2x^2 +
16x + 16) / (2x^2 - 4x + 1)^2
= (4/3x^4 - 16x^3 + 2x^2 + 16x + 16) /
(2x^2 - 4x + 1)^2
semoga terbantu