Matematika

Pertanyaan

tolong nomor 14 dong
tolong nomor 14 dong

1 Jawaban


  • [tex] \frac{1 - \cos(x) }{ \sin(x) } \times \frac{1 + \cos(x) }{1 + \cos(x) } \\ = \frac{1 - ( { \cos(x) }^{2}) }{( { \sin(x) })(1 + \cos(x) )} \\ = \frac{( { \sin(x) }^{2} )}{( \sin(x))(1 + \cos(x) )} \\ = \frac{ \sin(x) }{1 + \cos(x) } [/tex]

    ingat sifat identitas
    [tex]( { \sin(x) }^{2} ) + ( { \cos(x) }^{2} ) = 1[/tex]

    semoga membantu :)