tolong nomor 14 dong
Matematika
inggridtyaa
Pertanyaan
tolong nomor 14 dong
1 Jawaban
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1. Jawaban rinspirit95
[tex] \frac{1 - \cos(x) }{ \sin(x) } \times \frac{1 + \cos(x) }{1 + \cos(x) } \\ = \frac{1 - ( { \cos(x) }^{2}) }{( { \sin(x) })(1 + \cos(x) )} \\ = \frac{( { \sin(x) }^{2} )}{( \sin(x))(1 + \cos(x) )} \\ = \frac{ \sin(x) }{1 + \cos(x) } [/tex]
ingat sifat identitas
[tex]( { \sin(x) }^{2} ) + ( { \cos(x) }^{2} ) = 1[/tex]
semoga membantu :)