Matematika

Pertanyaan

tentukan persamaan garis (3,-2) dan tegak lurus y=2x-5

2 Jawaban

  • y = 2x - 5
    m1 = 2
    m2 = -1/2

    y - y1 = m(x - x1)
    y + 2 = -1/2 (x - 3)
    2y + 4 = -x + 3
    x + 2y + 4 - 3 = 0
    x + 2y + 1 = 0
  • y = 2x - 5
    m₁ = 2

    tegak lurus maka: m₂ = -1/2
    melalui garis (3, -2)

    y - y₁ = m₂(x - x₁)
    y + 2 = -1/2(x - 3)
    2(y + 2) = -1(x - 3)
    2y + 4 = -x + 3
    x + 2y + 4 - 3 = 0
    x + 2y + 1 = 0 ✔

Pertanyaan Lainnya