PR Matematika, mohon dibantu. jika log 7 basis 64 = x, tentukan nilai dari log 1/49 basis 128 Terimakasih

[tex]64_{log}7 = x \\ 2^{6}_{log}7 = x \\ \frac{1}{6}.2_{log}7 = x \\ 2_{log}7 = 6x \\ \\ 128_{log} \frac{1}{49} \\ \\ 2^{7}_{log}7^{-2} \\ \\ -\frac{2}{7}.2_{log}7 \\ \\ -\frac{2}{7}.6x = -\frac{12x}{7}[/tex]

[tex]64log7 = x[/tex]
[tex]2 ^{6}log7 = x[/tex]
[tex] \frac{1}{6}^{2}log7 = x [/tex]
[tex] ^{2} log7 = 6x[/tex]
-[tex] \frac{2}{7}[/tex][tex] 2^{7}log7 ^{-2} [/tex]
= -[tex] \frac{2}{7} [/tex] . [tex] ^{2}log7[/tex]
= -[tex] \frac{2}{7} [/tex] x 6[tex] x[/tex]
= -[tex] \frac{12}{7} [/tex][tex] x[/tex]