2log3=a dan 2log7 =b, maka 6log28 =......
Matematika
iftitahdwiulumi
Pertanyaan
2log3=a dan 2log7 =b, maka
6log28 =......
6log28 =......
1 Jawaban
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1. Jawaban keruasriki
=> (2log28)/(2log6)
=> (2log(4.7))/(2log(2.3))
=> (2(2log2) + 2log7) / (2log2 + 2log3)
=> (2(1) + b)/(1 + a)
=> (2+ b)/(1 + a)