[tex] \int\limits^a_b {(2x+3) ^{2} } \, dx = . [/tex]

misal:
(2x + 3) = u, maka:

ʃ u² dx
= ʃ 1/3 u³
= ʃ 1/3 (2x + 3)³
masukkan nilai a dan b.
= [1/3 (2x + 3)³] - [1/3 (2x + 3)³]
= [1/3 (2a + 3)³] - [1/3 (2b + 3)³]
= [1/3 ((2a)³ + 3(2a)²3 + 3.2a(3)² + (3)³] - [1/3 ((2b)³ + 3(2b)²3 + 3.2b(3)² + (3)³]
= [1/3 (8a³ + 18a² + 54a + 27)] - [1/3 (8b³ + 18b² + 54b + 27)]
= [8a³/3 + 6a² + 18a + 9] - [8b³/3 + 6b² + 18b + 9]
= 8a³/3 + 6a² + 18a + 9 - 8b³/3 - 6b² - 18b - 9
= 8a³/3 - 8b³/3 + 6a² - 6b² + 18a - 18b

Jadikan sebagai solusi terbaik, terimakasih