Matematika

Pertanyaan

Luas segitiga dimana a=15cm b=13cm dan c=10cm adalah...cm

2 Jawaban

  • Bab Segitiga

    Luas segitiga = √(s(s - a)(s - b)(s - c))
    dengan
    s = 1/2 × Keliling

    s = 1/2 × (a + b + c)
    s = 1/2 × (15 cm + 13 cm + 10 cm)
    s = 1/2 × 38 cm
    s = 19 cm

    Luas
    = √(19(19 - 15)(19 - 13)(19 - 10))
    = √(19(4)(6)(9))
    = 2 × 3 √(19 × 6)
    = 6√114 cm^2
  • s = 1/2 ( a + b + c)
    s = 1/2 (15 + 13 + 10)
    s = 19

    L = akar (s (s-a)(s-b)(s-c)
    L = akar (19(19-15)(19-13)(19-10))
    L = akar (19(4)(6)(9))
    L = 2 x 3 x akar (19 x 6)
    L = 6 akar 114 cm2

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