Matematika

Pertanyaan

nilai dari sin²45°sin²60°+cos²45°cos²60°/tan30°tan60°

1 Jawaban

  • sin 45° = (½)√2
    cos 45° = (½)√2
    sin 60° = (½)√3
    cos 60° = ½
    tan 30° = (⅓)√3
    tan 60° = √3

    (sin²45° sin²60° + cos²45° cos²60°)/(tan30° tan60°)
    = [(½√2)²(½√3)² + (½√2)²(½)²] / [(⅓√3)(√3)]
    = [(2/4)(3/4) + (2/4)(1/4)] / (3/3)
    = [(1/2)(3/4) + (1/2)(1/4)] / 1
    = 3/8 + 1/8
    = 4/8
    = 1/2

    semoga membantu, mohon dikoreksi bila ada kesalahan

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