nilai dari sin²45°sin²60°+cos²45°cos²60°/tan30°tan60°
Matematika
AnhitKonyep1940
Pertanyaan
nilai dari sin²45°sin²60°+cos²45°cos²60°/tan30°tan60°
1 Jawaban
-
1. Jawaban hadi2saputro
sin 45° = (½)√2
cos 45° = (½)√2
sin 60° = (½)√3
cos 60° = ½
tan 30° = (⅓)√3
tan 60° = √3
(sin²45° sin²60° + cos²45° cos²60°)/(tan30° tan60°)
= [(½√2)²(½√3)² + (½√2)²(½)²] / [(⅓√3)(√3)]
= [(2/4)(3/4) + (2/4)(1/4)] / (3/3)
= [(1/2)(3/4) + (1/2)(1/4)] / 1
= 3/8 + 1/8
= 4/8
= 1/2
semoga membantu, mohon dikoreksi bila ada kesalahan