suatu kerucut mampunyai tinggi 72 cm dan jari jari 21 cm tentukan luas selimut kerucut

Kerucut
t = 72
r = 21
s = √t²+ r²= √72²+21² = 75

Luas selimut = π r s
Ls = 22/7 . 21 , 75
Ls= 4.950 cm

s = √(r² + t²)
s = √(21² + 72²)
s = √(441 + 5184)
s = √5625
s = 75 cm

Luas selimut = πrs
= 22/7 × 21 × 75
= 66 × 75
= 4.950 cm²