Kimia

Pertanyaan

Tentukan PH larutan 100 my NH4OH 0.1 kN =1.8X 10–5

1 Jawaban

  • OH- = akar Kb Mb
    = akar 1,8.10^-5 x 0,1
    = akar 1,8.10^-6
    = 1,34.10^-3 M

    pOH = 3 - log 1,34
    pH = 11 + log 1,34

Pertanyaan Lainnya