Tentukan PH larutan 100 my NH4OH 0.1 kN =1.8X 10–5
Kimia
Ikaselvi
Pertanyaan
Tentukan PH larutan 100 my NH4OH 0.1 kN =1.8X 10–5
1 Jawaban
-
1. Jawaban ionkovalen
OH- = akar Kb Mb
= akar 1,8.10^-5 x 0,1
= akar 1,8.10^-6
= 1,34.10^-3 M
pOH = 3 - log 1,34
pH = 11 + log 1,34