rumus empiris suatu senyawa adalab (C4H7)n. jika massa molekul relatifnya 110, rumus molekul senyawa tsb adalah...

Mr C4H7 = 55 (rumus empiris)
Mr RE x n = Mr RM
55 x n = 110
n = 2

RM = (C4H7)2 = C8H14

Mr(C4H7)n = RE
(Ar.C x 4 + Ar.H x 7)n = 110
(12 x 4 + 1 x 4) = 110
(55)n = 110
n = 110/55
n : 2
maka rumus empirisnya..
(C4H7)2 yaitu C8H14