Diketahui sin A - cos A = 1/9, maka cosec A - sec A = ....
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Pertanyaan
Diketahui sin A - cos A = 1/9, maka cosec A - sec A = ....
1 Jawaban
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1. Jawaban Gallz22
[tex] (sin A - cos A = \frac{1}{9}) ^2[/tex]
[tex] sin^2 A +cos^2 A -2sinA.cosA = \frac{1}{81} [/tex]
[tex] sinA.cosA = \frac{40}{81} [/tex]
Maka,
=[tex] \frac{1}{sinA} - \frac{1}{cosA} [/tex]
=[tex] \frac{cosA - sinA} {cosA.sinA} [/tex]
=[tex] \frac{\frac{-1}{9}}{\frac{40}{81}} [/tex]
=[tex] \frac{-9}{40} [/tex]