himpunan penyelesaian dari persamaa kuadrat 2x pangkat 2 - 5x - 3x = 0

2x^2 - 5x - 3 = 0
2x^2 - 6x + x - 3 = 0
2x(x - 3) + (x - 3) = 0
(2x + 1)(x - 3) = 0

2x + 1 = 0
x = -1/2

x - 3 = 0
x = 3

HP = {-1/2 , 3}

2x² - 5x - 3 = 0
= (2x - 2)  (2x + 3) = 0
= (x - 1) (2x + 3) = 0
= x - 1 = 0
= x[tex] _{1} [/tex] = 1

= 2x + 3 = 0
= 2x = - 3
= x[tex]_{2} [/tex] = [tex] \frac{3}{2} [/tex]

Jadi, HP = {x[tex] _{1} [/tex] = 1 atau x[tex]_{2} [/tex] = [tex] \frac{3}{2} [/tex]}