bagaimana ini? bingung kalau soalnya dibalik bgini..

[tex]g(x)= 3x+2\\y=3x+2\\3x=y-2\\x=\frac{1}{3}y-\frac{2}{3}\\g^{-1}(x)=\frac{2}{3}x-\frac{2}{3} \\\\(g^{-1}of)(x)=g^{-1}(f(x))\\=g^{-1}(\frac{6+x}{x-8})\\=\frac{1}{3}(\frac{6+x}{x-8})-\frac{2}{3} \\ =\frac{6+x}{3(x-8)}-\frac{2(x-8)}{3(x-8)}\\=\frac{6+x-2(x-8)}{3(x-8)}\\=\frac{22-x}{3(x-8)}[/tex]

Maaf kalau sulit dimengerti.