Matematika

Pertanyaan

12 log 125 + 10 log 32 - 10 log 4 =

1 Jawaban

  • = ^12log 125 + ^10 log (32/4)
    = ^12log 125 + ^10log 8
    = ^12l0g 5³ + ^10log 2³
    = 3.^12log 5 + 3.^10log 2
    = 3(^12log 5 + ^10log 2)

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