Kelarutan garam berikut yang terkecil adalah... A.AgCl(Ksp = 1,6 x 10-10) B.AgCrO4(Ksp = 1,1 x 10-12) C.CaF2(Ksp = 4,0 x 10-11) D.Bi2S3(Ksp = 1 x 10-97) E.AuCl3
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Pertanyaan
Kelarutan garam berikut yang terkecil adalah...
A.AgCl(Ksp = 1,6 x 10-10)
B.AgCrO4(Ksp = 1,1 x 10-12)
C.CaF2(Ksp = 4,0 x 10-11)
D.Bi2S3(Ksp = 1 x 10-97)
E.AuCl3(Ksp = 3,2 x 10-23)
A.AgCl(Ksp = 1,6 x 10-10)
B.AgCrO4(Ksp = 1,1 x 10-12)
C.CaF2(Ksp = 4,0 x 10-11)
D.Bi2S3(Ksp = 1 x 10-97)
E.AuCl3(Ksp = 3,2 x 10-23)
1 Jawaban
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1. Jawaban ionkovalen
Jawaban
Kelarutan garam terkecil adalah Bi₂S₃ (Ksp = 1. 10⁻⁹⁷)
Penjelasan
AgCl
AgCl ---> Ag⁺ + Cl⁻
Ksp = s²
s = [tex]\sqrt{1,6~.10^{-10}}[/tex]
s = [tex]\sqrt{1,6}[/tex] . 10⁻⁵ M
AgCrO₄
AgCrO₄ ---> Ag⁺ + CrO₄⁻
Ksp = s²
s = [tex]\sqrt{1,1~.10^{-12}}[/tex]
s = [tex]\sqrt{1,1}[/tex] . 10⁻⁶ M
CaF₂
CaF₂ ---> Ca²⁺ + 2F⁻
Ksp = 4s³
s = [tex]\sqrt[3]{\frac{4}{4}~.10^{-11} }[/tex]
s = 1. [tex]10^{-5,5}[/tex] M
Bi₂S₃
Bi₂S₃ ---> 2Bi³⁺ + 3S²⁻
Ksp = 108s⁵
s = [tex]\sqrt[5]{\frac{1}{108}~.10^{-97} }[/tex]
s = [tex]\sqrt[5]{\frac{1}{108} }[/tex] [tex].10^{-19,4}[/tex] M
AuCl₃
AuCl₃ ---> Au³⁺ + 3Cl⁻
Ksp = 27s⁴
s = [tex]\sqrt[4]{\frac{3,2}{27}~.10^{-23} }[/tex]
s = [tex]\sqrt[4]{\frac{3,2}{27} }[/tex] [tex].10^{-5,75}[/tex] M
Pelajari lebih lanjut
- Pengaruh ion senama https://brainly.co.id/tugas/22438849, https://brainly.co.id/tugas/22496275, https://brainly.co.id/tugas/176316, https://brainly.co.id/tugas/15762184
- Kelarutan terbesar https://brainly.co.id/tugas/22446485, https://brainly.co.id/tugas/6321965
- Kelarutan terkecil https://brainly.co.id/tugas/10900731
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