Matematika

Pertanyaan

Lim x-->2, x^2-4/x+ akar 3x+10

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  • [tex]\lim_{x \to 2} \frac{x^{2}-4}{x+\sqrt{3x+10}} \\ = \lim_{x \to 2} \frac{x^{2}-4}{x+\sqrt{3x+10}} \times \frac{x-\sqrt{3x+10}}{x-\sqrt{3x+10}} \\ = \lim_{x \to 2} \frac{(x^{2}-4)(x-\sqrt{3x+10})}{x^{2}-(3x+10)} \\ = \frac{((2)^{2}-4)(2-\sqrt{3(2)+10})}{2^{2}-(3(2)+10)} \\ = \frac{0}{4-16} \\ = \frac{0}{-12} \\ = 0[/tex]

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